Ferial has it. Let’s say you’re using level 5 amps and normal finders (10 probes for enmatter = 0.5 ped / drop, ore = 1 ped / drop, etc.).

Adding in the amp TT, you’re now at 2.5 and 3 ped / drop, respectively. Just throwing out random numbers, but assuming for example your average TT drop is 90% ± 20% of the drop cost, you’re just shifting what that calculation is based on or where the center of variation is.

For unamped ore, that would be 0.7 to 1.1 ped

For level 5 amped ore, that would be 2.1 to 3.3 ped

Again, those aren’t hard numbers, just for concept. If you want to think in terms of multipliers, mining amps just increase the base value a “multiplier” is applied to. If you got lucky and found a 10 ped ore claim unamped, you theoretically would have hit 30 ped of you used a level 5 instead.

The danger with amps is you are more susceptible to No Resources Found math-wise. If you find nothing unamped, 0 is still close to what your average claim size is. That’s similar enough to your normal bell-shaped (sort of) curve for claim size. As you go to bigger amps, it becomes more bimodal as you jump between misses and claims, which can change the math of how averages work a bit.